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11=24x-4x^2
We move all terms to the left:
11-(24x-4x^2)=0
We get rid of parentheses
4x^2-24x+11=0
a = 4; b = -24; c = +11;
Δ = b2-4ac
Δ = -242-4·4·11
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-20}{2*4}=\frac{4}{8} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+20}{2*4}=\frac{44}{8} =5+1/2 $
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